Optimal. Leaf size=71 \[ -\frac{4 b (d+e x)^{9/2} (b d-a e)}{9 e^3}+\frac{2 (d+e x)^{7/2} (b d-a e)^2}{7 e^3}+\frac{2 b^2 (d+e x)^{11/2}}{11 e^3} \]
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Rubi [A] time = 0.0767092, antiderivative size = 71, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.077 \[ -\frac{4 b (d+e x)^{9/2} (b d-a e)}{9 e^3}+\frac{2 (d+e x)^{7/2} (b d-a e)^2}{7 e^3}+\frac{2 b^2 (d+e x)^{11/2}}{11 e^3} \]
Antiderivative was successfully verified.
[In] Int[(d + e*x)^(5/2)*(a^2 + 2*a*b*x + b^2*x^2),x]
[Out]
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Rubi in Sympy [A] time = 30.0454, size = 65, normalized size = 0.92 \[ \frac{2 b^{2} \left (d + e x\right )^{\frac{11}{2}}}{11 e^{3}} + \frac{4 b \left (d + e x\right )^{\frac{9}{2}} \left (a e - b d\right )}{9 e^{3}} + \frac{2 \left (d + e x\right )^{\frac{7}{2}} \left (a e - b d\right )^{2}}{7 e^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((e*x+d)**(5/2)*(b**2*x**2+2*a*b*x+a**2),x)
[Out]
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Mathematica [A] time = 0.0995112, size = 61, normalized size = 0.86 \[ \frac{2 (d+e x)^{7/2} \left (99 a^2 e^2+22 a b e (7 e x-2 d)+b^2 \left (8 d^2-28 d e x+63 e^2 x^2\right )\right )}{693 e^3} \]
Antiderivative was successfully verified.
[In] Integrate[(d + e*x)^(5/2)*(a^2 + 2*a*b*x + b^2*x^2),x]
[Out]
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Maple [A] time = 0.012, size = 63, normalized size = 0.9 \[{\frac{126\,{x}^{2}{b}^{2}{e}^{2}+308\,xab{e}^{2}-56\,x{b}^{2}de+198\,{a}^{2}{e}^{2}-88\,abde+16\,{b}^{2}{d}^{2}}{693\,{e}^{3}} \left ( ex+d \right ) ^{{\frac{7}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((e*x+d)^(5/2)*(b^2*x^2+2*a*b*x+a^2),x)
[Out]
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Maxima [A] time = 0.725436, size = 92, normalized size = 1.3 \[ \frac{2 \,{\left (63 \,{\left (e x + d\right )}^{\frac{11}{2}} b^{2} - 154 \,{\left (b^{2} d - a b e\right )}{\left (e x + d\right )}^{\frac{9}{2}} + 99 \,{\left (b^{2} d^{2} - 2 \, a b d e + a^{2} e^{2}\right )}{\left (e x + d\right )}^{\frac{7}{2}}\right )}}{693 \, e^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)*(e*x + d)^(5/2),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.206651, size = 235, normalized size = 3.31 \[ \frac{2 \,{\left (63 \, b^{2} e^{5} x^{5} + 8 \, b^{2} d^{5} - 44 \, a b d^{4} e + 99 \, a^{2} d^{3} e^{2} + 7 \,{\left (23 \, b^{2} d e^{4} + 22 \, a b e^{5}\right )} x^{4} +{\left (113 \, b^{2} d^{2} e^{3} + 418 \, a b d e^{4} + 99 \, a^{2} e^{5}\right )} x^{3} + 3 \,{\left (b^{2} d^{3} e^{2} + 110 \, a b d^{2} e^{3} + 99 \, a^{2} d e^{4}\right )} x^{2} -{\left (4 \, b^{2} d^{4} e - 22 \, a b d^{3} e^{2} - 297 \, a^{2} d^{2} e^{3}\right )} x\right )} \sqrt{e x + d}}{693 \, e^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)*(e*x + d)^(5/2),x, algorithm="fricas")
[Out]
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Sympy [A] time = 9.3233, size = 355, normalized size = 5. \[ \begin{cases} \frac{2 a^{2} d^{3} \sqrt{d + e x}}{7 e} + \frac{6 a^{2} d^{2} x \sqrt{d + e x}}{7} + \frac{6 a^{2} d e x^{2} \sqrt{d + e x}}{7} + \frac{2 a^{2} e^{2} x^{3} \sqrt{d + e x}}{7} - \frac{8 a b d^{4} \sqrt{d + e x}}{63 e^{2}} + \frac{4 a b d^{3} x \sqrt{d + e x}}{63 e} + \frac{20 a b d^{2} x^{2} \sqrt{d + e x}}{21} + \frac{76 a b d e x^{3} \sqrt{d + e x}}{63} + \frac{4 a b e^{2} x^{4} \sqrt{d + e x}}{9} + \frac{16 b^{2} d^{5} \sqrt{d + e x}}{693 e^{3}} - \frac{8 b^{2} d^{4} x \sqrt{d + e x}}{693 e^{2}} + \frac{2 b^{2} d^{3} x^{2} \sqrt{d + e x}}{231 e} + \frac{226 b^{2} d^{2} x^{3} \sqrt{d + e x}}{693} + \frac{46 b^{2} d e x^{4} \sqrt{d + e x}}{99} + \frac{2 b^{2} e^{2} x^{5} \sqrt{d + e x}}{11} & \text{for}\: e \neq 0 \\d^{\frac{5}{2}} \left (a^{2} x + a b x^{2} + \frac{b^{2} x^{3}}{3}\right ) & \text{otherwise} \end{cases} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((e*x+d)**(5/2)*(b**2*x**2+2*a*b*x+a**2),x)
[Out]
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GIAC/XCAS [A] time = 0.228469, size = 581, normalized size = 8.18 \[ \frac{2}{3465} \,{\left (462 \,{\left (3 \,{\left (x e + d\right )}^{\frac{5}{2}} - 5 \,{\left (x e + d\right )}^{\frac{3}{2}} d\right )} a b d^{2} e^{\left (-1\right )} + 33 \,{\left (15 \,{\left (x e + d\right )}^{\frac{7}{2}} e^{12} - 42 \,{\left (x e + d\right )}^{\frac{5}{2}} d e^{12} + 35 \,{\left (x e + d\right )}^{\frac{3}{2}} d^{2} e^{12}\right )} b^{2} d^{2} e^{\left (-14\right )} + 1155 \,{\left (x e + d\right )}^{\frac{3}{2}} a^{2} d^{2} + 132 \,{\left (15 \,{\left (x e + d\right )}^{\frac{7}{2}} e^{12} - 42 \,{\left (x e + d\right )}^{\frac{5}{2}} d e^{12} + 35 \,{\left (x e + d\right )}^{\frac{3}{2}} d^{2} e^{12}\right )} a b d e^{\left (-13\right )} + 22 \,{\left (35 \,{\left (x e + d\right )}^{\frac{9}{2}} e^{24} - 135 \,{\left (x e + d\right )}^{\frac{7}{2}} d e^{24} + 189 \,{\left (x e + d\right )}^{\frac{5}{2}} d^{2} e^{24} - 105 \,{\left (x e + d\right )}^{\frac{3}{2}} d^{3} e^{24}\right )} b^{2} d e^{\left (-26\right )} + 462 \,{\left (3 \,{\left (x e + d\right )}^{\frac{5}{2}} - 5 \,{\left (x e + d\right )}^{\frac{3}{2}} d\right )} a^{2} d + 33 \,{\left (15 \,{\left (x e + d\right )}^{\frac{7}{2}} e^{12} - 42 \,{\left (x e + d\right )}^{\frac{5}{2}} d e^{12} + 35 \,{\left (x e + d\right )}^{\frac{3}{2}} d^{2} e^{12}\right )} a^{2} e^{\left (-12\right )} + 22 \,{\left (35 \,{\left (x e + d\right )}^{\frac{9}{2}} e^{24} - 135 \,{\left (x e + d\right )}^{\frac{7}{2}} d e^{24} + 189 \,{\left (x e + d\right )}^{\frac{5}{2}} d^{2} e^{24} - 105 \,{\left (x e + d\right )}^{\frac{3}{2}} d^{3} e^{24}\right )} a b e^{\left (-25\right )} +{\left (315 \,{\left (x e + d\right )}^{\frac{11}{2}} e^{40} - 1540 \,{\left (x e + d\right )}^{\frac{9}{2}} d e^{40} + 2970 \,{\left (x e + d\right )}^{\frac{7}{2}} d^{2} e^{40} - 2772 \,{\left (x e + d\right )}^{\frac{5}{2}} d^{3} e^{40} + 1155 \,{\left (x e + d\right )}^{\frac{3}{2}} d^{4} e^{40}\right )} b^{2} e^{\left (-42\right )}\right )} e^{\left (-1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)*(e*x + d)^(5/2),x, algorithm="giac")
[Out]